Injection Molding worked example
Mold Cooling Time with maximum part wall thickness of 6.25 mm: a worked example
Push maximum part wall thickness up to 6.25 mm and the picture changes. This example computes every intermediate figure at that operating point. Use this to estimate cooling time during mold design, optimize cycle time, or validate simulation results against a simplified analytical estimate.
The inputs for this scenario
- Maximum part wall thickness: 6.25 mm (raised for this scenario; the documented default is 2.5)
- Cooling rate factor (thermal diffusivity based): 3.2 sec/mm² (unchanged)
- Thickness geometry exponent: 2 x (unchanged)
Working through the calculation
- Applying the documented formula (Cooling time = Cooling rate factor x (Wall thickness ^ Geometry exponent)) to the inputs above produces each figure below.
- At this operating point the engine returns 40 sec for result, the number this scenario is built around.
- At this operating point the engine returns 40 value for thickness factor product.
- At this operating point the engine returns 1 x for multiplier.
- At this operating point the engine returns 20 value for factor a x b.
How this compares with the baseline
- Against the tool's baseline example, where maximum part wall thickness sits at 2.5 mm and the headline result is 16 sec, this scenario comes in 150% above the baseline at 40 sec.
- It computes the cooling phase duration in seconds by multiplying the resin cooling factor by wall thickness raised to the geometry exponent. The value of this scenario is the size of the gap it exposes: that gap, priced out over a year, is the budget you can justify spending to close it.
Results at a glance
- Result: 40 sec (headline result)
- Thickness factor product: 40 value
- Multiplier: 1 x
- Factor A x B: 20 value
Run it with your numbers
- Every input above is editable in the live Mold Cooling Time calculator, which recalculates instantly and can be shared with the inputs intact.
Last reviewed 2026-05-12.