Metals, Steel, Aluminum & Coil Processing worked example
Coil Weight with strip width of 120 in: a worked example
Push strip width up to 120 in and the picture changes. This example computes every intermediate figure at that operating point. Use it when a material handler or planner needs a coil weight from dimensions before staging, craning, or booking freight.
The inputs for this scenario
- Strip width: 120 in (raised for this scenario; the documented default is 48)
- Coil length: 12,000 in (unchanged)
- Gauge thickness: 0.06 in (unchanged)
- Material density: 0.28 lb/in³ (unchanged)
Working through the calculation
- Applying the documented formula (Coil weight = strip width × coil length × gauge thickness × material density) to the inputs above produces each figure below.
- At this operating point the engine returns 24,421 lb for coil weight, the number this scenario is built around.
- At this operating point the engine returns 86,112 value for base product.
- At this operating point the engine returns 0.28 x for multiplier.
- At this operating point the engine returns 1,440,000 value for factor a x b.
How this compares with the baseline
- Against the tool's baseline example, where strip width sits at 48 in and the headline result is 9,769 lb, this scenario comes in 150% above the baseline at 24,421 lb.
- It multiplies strip width, coil length, gauge thickness, and material density to return the theoretical weight of a flat strip coil in pounds. The value of this scenario is the size of the gap it exposes: that gap, priced out over a year, is the budget you can justify spending to close it.
Results at a glance
- Coil weight: 24,421 lb (headline result)
- Base product: 86,112 value
- Multiplier: 0.28 x
- Factor A x B: 1,440,000 value
Run it with your numbers
- Every input above is editable in the live Coil Weight calculator, which recalculates instantly and can be shared with the inputs intact.
Last reviewed 2026-05-12.