OEE & Factory Performance worked example

Minor Stop Loss with number of minor stops of 20 stops: a worked example

This worked example runs the minor stop loss numbers for a tougher week than the baseline: number of minor stops of 20 stops instead of the typical 40 stops. Quantify minor-stop loss for OEE & Factory Performance — the minutes lost to short, frequent stoppages.

The inputs for this scenario

  • Number of minor stops: 20 stops (the input this scenario stresses; the baseline uses 40)
  • Average stop duration: 1.5 min (held at the documented default)

Working through the calculation

  • The calculation starts from the formula this tool documents: Minor-stop loss = number of minor stops × average stop duration.
  • Minor-stop loss works out to 30 min at these inputs, and this is the headline figure for the scenario.
  • Minor stops works out to 20 stops at these inputs.
  • Avg stop duration works out to 1.5 min at these inputs.
  • Loss in hours works out to 0.5 hr at these inputs.

How this compares with the baseline

  • Against the tool's baseline example, where number of minor stops sits at 40 stops and the headline result is 60 min, this scenario comes in 50% below the baseline at 30 min.
  • Use it when you've tallied minor stops from a shift or a machine-data export and want to convert that count into a performance-loss figure for an OEE review or a Pareto of losses. A result at this level usually justifies acting on the stressed input before touching anything else, because every other figure in the table is downstream of it.

Results at a glance

  • Minor-stop loss: 30 min (headline result)
  • Minor stops: 20 stops
  • Avg stop duration: 1.5 min
  • Loss in hours: 0.5 hr

Run it with your numbers

  • To rerun this with your own numbers, open the live Minor Stop Loss calculator, set number of minor stops to your actual value, and adjust the remaining inputs to match your operation.

Last reviewed 2026-05-12.