How do you calculate conveyor chain pull?

Multiply the total moving load on the chain by a friction-and-incline factor. With 2,800 lb of moving load and a 0.18 factor, estimated chain pull is 504 lb force.

What is a typical friction factor for conveyor chain?

Roller chain on hardened tracks often runs 0.10-0.20 on the level; sliding chain or added incline pushes it higher. The 0.18 used here reflects modest friction with a small grade contribution.

What does the per-hour figure mean?

It is the estimated pull averaged over the operating time basis - 504 lb force over 8 hr gives 63 lb force/hr. It is a normalizing figure for comparing duty, not an instantaneous force.

Chain pull vs chain tension - are they the same?

Chain pull is the net force the drive adds to move the load; chain tension is the actual force in the chain at a given point, which builds around the loop. Pull is the starting point for tension analysis.

Why is the moving load so important?

Pull scales linearly with moving load, so it is the dominant input. Doubling the 2,800 lb load to 5,600 lb doubles estimated pull to about 1,008 lb force at the same 0.18 factor.

Does this size the motor directly?

Not by itself. Multiply chain pull by chain speed to get power, then add drive efficiency and a service factor before selecting the motor and reducer.

Conveyors calculator

Conveyor Chain Pull Calculator

Conveyor chain pull is the tangential force the drive must apply to keep the loaded chain moving against friction and grade. Maintenance and drive-sizing engineers use it as a first-pass estimate before specifying motor torque, sprocket size and chain strength. The estimate multiplies everything riding on the chain by a combined friction-and-incline factor, giving the force the drive sees at the headshaft. It matters because under-estimating chain pull burns drives and snaps chain, while over-estimating wastes money on oversized motors and reducers.

What this calculator does

Estimate required chain pull from moving load, friction or incline factor, and operating time basis.
a conveyor designer needs a quick chain-pull estimate before selecting a drive or requesting a supplier quote
It estimates the chain pull in lb force from the total moving load and a combined friction/incline factor, and expresses it as an average per operating hour.

Formula used

Estimated chain pull = total moving load × friction and incline factor
Average pull per operating hour = estimated chain pull ÷ operating time basis

Inputs explained

Total moving chain load:
Friction and incline pull factor:
Operating time basis:

How to use the result

Use it for early drive and chain sizing, for sanity-checking a vendor's quoted pull, or when load on an existing line changes.
The single combined factor lumps together rolling friction, sliding friction and grade; it is a rough estimate and does not replace a detailed pull analysis around the full chain path with tension build-up.

Current U.S. benchmarks

The U.S. has 21,668 machinery manufacturing establishments employing about 1,086,146 workers (Census County Business Patterns, 2023).

Common questions

How do you calculate conveyor chain pull? Multiply the total moving load on the chain by a friction-and-incline factor. With 2,800 lb of moving load and a 0.18 factor, estimated chain pull is 504 lb force.
What is a typical friction factor for conveyor chain? Roller chain on hardened tracks often runs 0.10-0.20 on the level; sliding chain or added incline pushes it higher. The 0.18 used here reflects modest friction with a small grade contribution.
What does the per-hour figure mean? It is the estimated pull averaged over the operating time basis - 504 lb force over 8 hr gives 63 lb force/hr. It is a normalizing figure for comparing duty, not an instantaneous force.
Chain pull vs chain tension - are they the same? Chain pull is the net force the drive adds to move the load; chain tension is the actual force in the chain at a given point, which builds around the loop. Pull is the starting point for tension analysis.
Why is the moving load so important? Pull scales linearly with moving load, so it is the dominant input. Doubling the 2,800 lb load to 5,600 lb doubles estimated pull to about 1,008 lb force at the same 0.18 factor.

Last reviewed 2026-05-12.